What is the percent by mass of oxygen in a gaseous mixture whose molar composition is 0.500% CO_2 and 99.500% air?

Question Show transcribed image text The Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO_2) in air a worker can breathe at 0.500% by mole. If dry Ice (solid CO_2) is sublimating (becoming a gas) in a room at a rate of 0.800 mol/min what is the minimum rate that fresh air has to be supplied to the room so that the concentration of CO_2 in the room doesnt exceed 0.500% by mole? Assume the room Is well mixed and the volume of the solid dry ice does not change. What is the percent by mass of oxygen in a gaseous mixture whose molar composition is 0.500% CO_2 and 99.500% air? The composition of air is 21% mole O_2 79% mole N_2 and has an average molar mass of 29.0 g/mol. The percent by mass of oxygen in a gaseous mixture is equal to the mass flow rate of oxygen divided by the mass flow rate of all other components multiplied by 100%.

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